{"id":104780,"date":"2021-01-29T16:03:32","date_gmt":"2021-01-29T10:33:32","guid":{"rendered":"https:\/\/www.vskills.in\/certification\/tutorial\/?page_id=104780"},"modified":"2024-04-12T14:28:13","modified_gmt":"2024-04-12T08:58:13","slug":"summaries-and-subscripting","status":"publish","type":"page","link":"https:\/\/www.vskills.in\/certification\/tutorial\/summaries-and-subscripting\/","title":{"rendered":"Summaries and Subscripting"},"content":{"rendered":"\n<p>Let&#8217;s suppose we&#8217;ve collected some data from an experiment and stored them in an object x:<\/p>\n\n\n\n<p>&gt; x&lt;-c(7.5,8.2,3.1,5.6,8.2,9.3,6.5,7.0,9.3,1.2,14.5,6.2)<\/p>\n\n\n\n<p>Some simple summary statistics of these data can be produced:<\/p>\n\n\n\n<p>&gt; mean(x)<\/p>\n\n\n\n[1] 7.216667<\/p>\n\n\n\n<p>&gt; var(x)<\/p>\n\n\n\n[1] 11.00879<\/p>\n\n\n\n<p>&gt; summary(x)<\/p>\n\n\n\n<p>Min. 1st Qu. Median Mean 3rd Qu. Max.<\/p>\n\n\n\n<p>1.200 6.050 7.250 7.217 8.475 14.500<\/p>\n\n\n\n<p>which should all be self explanatory. It may be, however, that we subsequently learn that the first 6 data correspond to measurements made on one machine, and the second six on another machine. This might suggest summarizing the two sets of data separately, so we would need to extract from x the two relevant sub-vectors. This is achieved by subscripting:<\/p>\n\n\n\n<p>&gt; x[1:6]\n\n\n\n<p>and<\/p>\n\n\n\n<p>&gt; x[7:12]\n\n\n\n<p>give the relevant sub-vectors. Hence,<\/p>\n\n\n\n<p>&gt; summary(x[1:6])<\/p>\n\n\n\n<p>Min. 1st Qu. Median Mean 3rd Qu. Max.<\/p>\n\n\n\n<p>3.100 6.075 7.850 6.983 8.200 9.300<\/p>\n\n\n\n<p>&gt; summary(x[7:12])<\/p>\n\n\n\n<p>Min. 1st Qu. Median Mean 3rd Qu. Max.<\/p>\n\n\n\n<p>1.200 6.275 6.750 7.450 8.725 14.500<\/p>\n\n\n\n<p>Other subsets can be created in the obvious way. For example:<\/p>\n\n\n\n<p>&gt; x[c(2,4,9)]\n\n\n\n[1] 8.2 5.6 9.3<\/p>\n\n\n\n<p>Negative integers can be used to exclude particular elements. For example x[-(1:6)] has the same effect as x[7:12].<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Let&#8217;s suppose we&#8217;ve collected some data from an experiment and stored them in an object x: &gt; x&lt;-c(7.5,8.2,3.1,5.6,8.2,9.3,6.5,7.0,9.3,1.2,14.5,6.2) Some simple summary statistics of these data can be produced: &gt; mean(x) [1] 7.216667 &gt; var(x) [1] 11.00879 &gt; summary(x) Min. 1st Qu. Median Mean 3rd Qu. Max. 1.200 6.050 7.250 7.217 8.475 14.500 which should all&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-104780","page","type-page","status-publish","hentry"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v24.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Summaries and Subscripting - Tutorial<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.vskills.in\/certification\/tutorial\/summaries-and-subscripting\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Summaries and Subscripting - Tutorial\" \/>\n<meta property=\"og:description\" content=\"Let&#8217;s suppose we&#8217;ve collected some data from an experiment and stored them in an object x: &gt; x&lt;-c(7.5,8.2,3.1,5.6,8.2,9.3,6.5,7.0,9.3,1.2,14.5,6.2) Some simple summary statistics of these data can be produced: &gt; mean(x) [1] 7.216667 &gt; var(x) [1] 11.00879 &gt; summary(x) Min. 1st Qu. Median Mean 3rd Qu. 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